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360 1. Each central angle c measures n . (n 2)180 2. Each interior angle i measures . n 360 3. Each exterior angle e measures n .

Because X ( e j w ) = 0 for Iwl n/4, if the system is to be linear and shift-invariant, Y (el") must be equal to zero for lo1 > n / 4 (an LSI system cannot produce new frequencies). Because this is not the case, no LSI system will produce the given input-output pair. (d) For the last system, we are given x ( n ) = u(n) and y(n) = S(n). Therefore, and As in part (a),there is a unique LSI system that produces this input-output pair, and the frequency response of this system is

22 .3

Thus for the regular pentagon ABCDE of Fig. 10-2, m/AOB and m/ABS 360 n 360 5 72 m/ABC m/ABC m/ABS (n 180 2) 180 n (5 2) 180 5 108

Case 3:

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FOURIER ANALYSIS Note that we may write x ( n ) as the sum of a left-sided sequence and a right-sided sequence as follows:

Fig. 10-2

where the last term is included to remove the extra term that is introduced at n = 0 by the two exponential sequences. The DTFT of the first term is

10.1 Finding measures of lines and angles in a regular polygon (a) Find the length of a side s of a regular pentagon if the perimeter p is 35. (b) Find the length of the apothem a of a regular pentagon if the radius of the inscribed circle is 21. (c) In a regular polygon of five sides, find the measures of the central angle c, the exterior angle e, and the interior angle i. (d) If an interior angle of a regular polygon measures 108 , find the measures of the exterior angle and the central angle and the number of sides.

Therefore,

Fig. 10-3

I - 1--

17.7 Prove the mean-value theorem (Theorem 17.2).

to show that x ( n ) may be recovered from X(eju) as follows:

(b) Since an apothem r is a radius of the inscribed circle, it has length 21. (c) n (d) m/i 5. Then m/c 360 n 360 5 72 ; m/e 360 n 72 ; m/i 360 n ,n 180 m/e 108 .

To recover x ( n ) from X(eJm),it is necessary to "filter out" all of the terms in the sum except one (i.e., we must isolate a single term in the sum). This may be done by multiplying both sides of the equation by a complex exponential, elnw:

5. (See Fig. 10-3.)

and integrating from -n to n,

Proving a regular-polygon problem stated in words Prove that a vertex angle of a regular pentagon is trisected by diagonals drawn from that vertex.

Then g is continuous over [a, b] and differentiable on (a, b). Moreover, g(a) = f (a) f (b) f (a) (a a) f (a) = f (a) 0 f (a) = 0 b a f (b) f (a) g(b) = f (b) (b a) f (a) = f (b) (f (b) f (a)) f (a) b a = f (b) f (b) + f (a) f (a) = 0

Using the orthogonality of the complex exponentials, it follows that the integral is zero when k # n , and it is equal to 2n when k = n. Therefore,

Plan: Circumscribe a circle and show that angles BAC, CAD, and DAE are congruent. PROOF:

s(n)

Statements 1. ABCDE is a regular pentagon. 2. Circumscribe a circle about ABCDE. 3. BC CD DE 4. BC > CD >DE 5. /BAC /CAD /DAE

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